Pyramid 1021
Preview $$U_{1021}(x, y) = \frac{\left(x + 1\right)^{3}}{\left(1 - y\right)^{2}}$$
Pyramid 1022
Preview $$U_{1022}(x, y) = \frac{\left(x + 1\right)^{3}}{\left(1 - y\right)^{3}}$$
Pyramid 1023
Preview $$U_{1023}(x, y) = \frac{\left(1 - \sqrt{1 - 4 y}\right) \left(x + 1\right)^{3}}{2 y}$$
Pyramid 1024
Preview $$U_{1024}(x, y) = \frac{\left(1 - \sqrt{1 - 4 y}\right)^{2} \left(x + 1\right)^{3}}{4 y^{2}}$$
Pyramid 1025
Preview $$U_{1025}(x, y) = \frac{\left(1 - \sqrt{1 - 4 y}\right)^{3} \left(x + 1\right)^{3}}{8 y^{3}}$$
Pyramid 1026
Preview $$U_{1026}(x, y) = \left(y + 1\right)^{2} \sqrt{4 x \left(y + 1\right)^{3} + 1}$$
Pyramid 1027
Preview $$U_{1027}(x, y) = \frac{\left(x + 1\right)^{3} \left(- 2 y - \sqrt{1 - 4 y} + 1\right)^{2}}{4 y^{4}}$$
Pyramid 1028
Preview $$U_{1028}(x, y) = \frac{\left(x + 1\right)^{3} \left(- 2 y - \sqrt{1 - 4 y} + 1\right)^{3}}{8 y^{6}}$$
Pyramid 1029
Preview $$U_{1029}(x, y) = \frac{\left(y + 1\right)^{3}}{1 - x}$$
Pyramid 1030
Preview $$U_{1030}(x, y) = \frac{1}{\left(1 - x\right) \left(1 - y\right)^{3}}$$
Pyramid 1031
Preview $$U_{1031}(x, y) = \frac{\left(1 - \sqrt{1 - 4 y}\right)^{3}}{y^{3} \left(8 - 8 x\right)}$$
Pyramid 1032
Preview $$U_{1032}(x, y) = \frac{\left(- 2 y - \sqrt{1 - 4 y} + 1\right)^{2}}{y^{4} \left(4 - 4 x\right)}$$
Pyramid 1033
Preview $$U_{1033}(x, y) = \frac{\left(- 2 y - \sqrt{1 - 4 y} + 1\right)^{3}}{y^{6} \left(8 - 8 x\right)}$$
Pyramid 1034
Preview $$U_{1034}(x, y) = \frac{\left(y + 1\right)^{3}}{\left(1 - x\right)^{2}}$$
Pyramid 1035
Preview $$U_{1035}(x, y) = \frac{\left(1 - \sqrt{1 - 4 y}\right)^{2}}{4 y^{2} \left(1 - x\right)^{2}}$$
Pyramid 1036
Preview $$U_{1036}(x, y) = \frac{\left(1 - \sqrt{1 - 4 y}\right)^{3}}{8 y^{3} \left(1 - x\right)^{2}}$$
Pyramid 1037
Preview $$U_{1037}(x, y) = \left(y + 1\right)^{7} \sqrt{4 x \left(y + 1\right)^{3} + 1}$$
Pyramid 1038
Preview $$U_{1038}(x, y) = \frac{\left(- 2 y - \sqrt{1 - 4 y} + 1\right)^{2}}{4 y^{4} \left(1 - x\right)^{2}}$$
Pyramid 1039
Preview $$U_{1039}(x, y) = \frac{\left(- 2 y - \sqrt{1 - 4 y} + 1\right)^{3}}{8 y^{6} \left(1 - x\right)^{2}}$$
Pyramid 1040
Preview $$U_{1040}(x, y) = \frac{y + 1}{\left(1 - x\right)^{3}}$$
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