$$U_{130}(x, y) = \frac{1}{- 4 y + \left(- x + y + 1\right)^{2}}$$

$$T_{130}(n, m, k) = \frac{{\binom{k + m}{k - 1}} {\binom{k + n - 1}{k - 1}} {\binom{2 k + 2 m + 2 n}{2 m + 1}} {\binom{2 k + m + n - 1}{k - 1}}}{2 {\binom{2 k - 2}{k - 1}} {\binom{2 k + 2 m}{2 k - 2}}}$$