$$U_{1072}(x, y) = \frac{\left(1 - \sqrt{1 - 4 x}\right)^{3} \left(- 2 y - \sqrt{1 - 4 y} + 1\right)^{2}}{32 x^{3} y^{4}}$$

$$T_{1072}(n, m, k) = \frac{6 k^{2} {\binom{4 k + 2 m}{m}} {\binom{3 k + 2 n - 1}{n}}}{\left(2 k + m\right) \left(3 k + n\right)}$$